Isn't this a secondary amine?
If my drawing is right, yes.
ring-NH(CH3)
benzene ring-N-H-CH3
H
\
N-benzene ring
/
CH3
select the class of compound from the choice below.
1-acetal
2-alcohol
3-alkene
4-amide
5-amine
6-carboxylic acid
7-ester
8-haloalkane
2 answers
do you think is amine