There are two question in this problem:
a) Find "q" for the sample burned.
b) find "q" for 1.25 moles of C6H6.
Your numerical answer for the first part is correct but you are not paying attention to unit labels. It is mislabeled.
For the second part, to find kilojoules/mole, you DIVIDE kilojoules by moles. If you LABEL each measurment, that would suggest to you how to use those measurements.
146.77 kJ / 0.0449345 mol = 3270 kJ/mole
(That means 3270 kJ given off by 1 mole)
Now, how do you find the heat released by 1.25 moles of benzene???
BobPursley has helped you and observed you longer than I have. He is trying to tell you something that could benefit you: Pay more attention to the strategy and logic of a solution. That includes unit labels. None of us are good at something, or anything, unless we are completely focused on it.