Asked by Luellen
A ball is thrown vertically upward from a window with an initial velocity of 10m/s. if it hits the ground below the window 5.0s later, what is the height of the window...can you tell me the steps on how to do this please...
Answers
Answered by
bobpursley
assume all heights are from the middle of the window.
hf=hi+vi*t-1/2 g t^2
hf=unknown
hi=zero
vi=10
t=5
g =-9.8m/s^2
calculate
hf=hi+vi*t-1/2 g t^2
hf=unknown
hi=zero
vi=10
t=5
g =-9.8m/s^2
calculate
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