Asked by kate
A ball is thrown 60m vertically into the air. What was its initial velocity? How much time does it take to reach the highest point?
Answers
Answered by
oobleck
at the top, its PE = mgh
when thrown, that was all KE = 1/2 mv^2
so, v^2 = 2gh
now, having v, and knowing that velocity is zero at the top, find the time t, using
v - gt = 0
when thrown, that was all KE = 1/2 mv^2
so, v^2 = 2gh
now, having v, and knowing that velocity is zero at the top, find the time t, using
v - gt = 0
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