Question
A total of $15,000 is invested into two accounts. One of the accounts earns 12% per year and the other earns 10% per year. If the total interest earned in the first year is $1600, how much is invested in each account?
1.) Define the variable(s) and what they stand for.
2.) Set up an equation
3.) State the solutions
1.) Define the variable(s) and what they stand for.
2.) Set up an equation
3.) State the solutions
Answers
amount invested at 12% --- x
amount invested at 10% --- 15000-x
.12x + .10(15000-x = 1600
12x + 10(15000-x) = 160000
12x + 150000 - 10x = 160000
2x = 10000
x = 5000
so $5000 invested at 12% and $10000 invested at 10%
check:
.12(5000) + .1(10000) = 1600
YUP!
amount invested at 10% --- 15000-x
.12x + .10(15000-x = 1600
12x + 10(15000-x) = 160000
12x + 150000 - 10x = 160000
2x = 10000
x = 5000
so $5000 invested at 12% and $10000 invested at 10%
check:
.12(5000) + .1(10000) = 1600
YUP!
12
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