Asked by Anonymous
A total of $4,000 was invested, part of it at 6% interest and the remainder at 8%. If the total yearly interest amount is $260, how much was invested at 6%
Answers
Answered by
mathhelper
6% investment --- x
8% investment = 4000-x
.06x + .08(4000-x) = 260
times 100
6x + 8(4000-x) = 26000
solve for x
8% investment = 4000-x
.06x + .08(4000-x) = 260
times 100
6x + 8(4000-x) = 26000
solve for x
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