Asked by ugh
A charge q1 = 5 ìC is at the origin. A second charge q2 = -3 ìC is on the x-axis, 0.8 m from the origin. The electric field at a point on the y-axis, 0.5 m from the origin is:
I don't understand the question please help . Thanks for reading
I don't understand the question please help . Thanks for reading
Answers
Answered by
Elena
q₁ = 5 μC =5•10⁻⁶ C,
q₂ = - 3 μC = - 3•10⁻⁶ C,
r₁ =0.5 m,
r₂ = 0.8 m.
k =9•10⁹ N•m²/C²
E₁=k•q₁/ r₁², (directed ↑)
E₂ = k•q₂/ r₂², (directed ↑)
vector E= vector E₁+vectorE₂
The magnitude of vector E is directed ↗ and is calculated using the cosine law.
tanα =0.8/0.5=1.6
α =58⁰
E=sqrt{E₁²+E₂²-2E₁E₂cosα} = …
q₂ = - 3 μC = - 3•10⁻⁶ C,
r₁ =0.5 m,
r₂ = 0.8 m.
k =9•10⁹ N•m²/C²
E₁=k•q₁/ r₁², (directed ↑)
E₂ = k•q₂/ r₂², (directed ↑)
vector E= vector E₁+vectorE₂
The magnitude of vector E is directed ↗ and is calculated using the cosine law.
tanα =0.8/0.5=1.6
α =58⁰
E=sqrt{E₁²+E₂²-2E₁E₂cosα} = …
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.