Asked by Katie
The kinetic energy of a proton is half its internal energy. What is the proton's speed?
Kinetic energy is (Yu - 1) (mp) (c)^2
= 1/2 (mp) (c)^2
Yu = 1.5
Yu = 1/(square root) 1 - (u/c)^2
1/(square root) 1 - (u/c)^2 = 1.5
u= 0.745c
How do I solve for u? I'm extremely confused on how to do this. I know you square 1/(square root) 1 - (u/c)^2 to both sides esp. 1.5 to get rid of the square root. But up to there I'm confused to how to solve for u
Kinetic energy is (Yu - 1) (mp) (c)^2
= 1/2 (mp) (c)^2
Yu = 1.5
Yu = 1/(square root) 1 - (u/c)^2
1/(square root) 1 - (u/c)^2 = 1.5
u= 0.745c
How do I solve for u? I'm extremely confused on how to do this. I know you square 1/(square root) 1 - (u/c)^2 to both sides esp. 1.5 to get rid of the square root. But up to there I'm confused to how to solve for u
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