Asked by Becca
                Rationalize each expression by building perfect nth root factors for each denominator. Assume all variables represent positive quantities.  I don’t understand how to compute these. Also I don’t have the square root sign so I typed it out where it would be and the number before or after. 
1. -4/Square root 20
2. Square root of 125/12n^3
3. Square root 10-3 /Square root 3 +Square root 2
4. 7+ square root 6 /3-3 square root 2
            
            
        1. -4/Square root 20
2. Square root of 125/12n^3
3. Square root 10-3 /Square root 3 +Square root 2
4. 7+ square root 6 /3-3 square root 2
Answers
                    Answered by
            Steve
            
    -4/√20 = -4√20/20 = -1/5 √20 = -2/5 √5
√(125/n^3) = √(25/n^2) √(5/n) = 5/n √(5/n)
= 5/n √(5n/n^2) = 5/n^2 √(5n)
(√10-3)/(√3+√2)
= (√10-3)(√3-√2) / (3-2)
= √30-3√3-√20+3√2
= 3√2-3√3-2√5+√30
(7+√6)/(3-√2)
= (7+√6)(3+√2) / (9-2)
= (21+3√6+7√2+√12)/7
= 1/7 (21 + 3√6 + 7√2 + 2√3)
    
√(125/n^3) = √(25/n^2) √(5/n) = 5/n √(5/n)
= 5/n √(5n/n^2) = 5/n^2 √(5n)
(√10-3)/(√3+√2)
= (√10-3)(√3-√2) / (3-2)
= √30-3√3-√20+3√2
= 3√2-3√3-2√5+√30
(7+√6)/(3-√2)
= (7+√6)(3+√2) / (9-2)
= (21+3√6+7√2+√12)/7
= 1/7 (21 + 3√6 + 7√2 + 2√3)
                    Answered by
            corrine
            
    8*/81-6/16
please help
    
please help
                    Answered by
            Nocholas
            
    1/3 + 3/x 1/9 - 9/x square
    
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.