Asked by Teresa
A common stock is just paid an annual dividend of $2 yesterday. The dividend is expeccted to grow at 8% annually for the next 3 years, after which is will grow at 4% in perpetuity. The appropriate discount rate is 12%. What is the priceof the stock?
What I know:
Differential growth
DIV=2
g1=.08
g2=.04
r=.12
yr.end 5=Div4(1+g2)=2.52(1.04)=2.6208
p4=DIV5/r-g2=2.6208/.12-.04=32.76 FV
p4/(1+r)^4=32.76/1.12^4=20.82
Present Value of all Div as of yr end 0 is 20.82 + 32.76 =
??? not sure about this step
What I know:
Differential growth
DIV=2
g1=.08
g2=.04
r=.12
yr.end 5=Div4(1+g2)=2.52(1.04)=2.6208
p4=DIV5/r-g2=2.6208/.12-.04=32.76 FV
p4/(1+r)^4=32.76/1.12^4=20.82
Present Value of all Div as of yr end 0 is 20.82 + 32.76 =
??? not sure about this step
Answers
Answered by
Damon
Perhaps my reply to your previous question would help. On the other hand perhaps I am way off base not being a financial type at all.
by the way, my g for geometric series is starting value.
my r is ratio of value at year (n+1) to value at year n.
in that case sum of infinite series is g/(1-r)
by the way, for just n terms
sum = g + g r + g r^2 +...+ g r^(n-1)
= g (1-r^n)/(1-r)
by the way, my g for geometric series is starting value.
my r is ratio of value at year (n+1) to value at year n.
in that case sum of infinite series is g/(1-r)
by the way, for just n terms
sum = g + g r + g r^2 +...+ g r^(n-1)
= g (1-r^n)/(1-r)
Answered by
Damon
let's see what the dividends are worth after 3 years (n = 4 because we start at the beginning of year one and the end of the other years)
V3 = 2 + 2(1.08/1.12) + 2(1.08/1.12)^2...
g = 2
r = 1.08/1.12 = .9463
so
sum after three years = 2(1-.9463^3)/(1-.9463) = 2(.1526/.0537) = 5.683
now we go on forever at 4%
g = 5.683
r = 1.04/1.12 = .9286
sum to infinity = 5.683/(1-.9286) = 79.56
V3 = 2 + 2(1.08/1.12) + 2(1.08/1.12)^2...
g = 2
r = 1.08/1.12 = .9463
so
sum after three years = 2(1-.9463^3)/(1-.9463) = 2(.1526/.0537) = 5.683
now we go on forever at 4%
g = 5.683
r = 1.04/1.12 = .9286
sum to infinity = 5.683/(1-.9286) = 79.56
Answered by
Damon
wait a minute, we have to subtract the first three years at 4% off the infinite 4% years because we did those years separately with 8%
sum at 4% after three = 2(1-.9286^3)/(1-.9286)
= 2*(.1993/.0714) = 5.583
so it is
79.56 - 5.58 = 73.98
sum at 4% after three = 2(1-.9286^3)/(1-.9286)
= 2*(.1993/.0714) = 5.583
so it is
79.56 - 5.58 = 73.98
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