A sample of steam with a mass of 0.553 g and at a temperature of 100 degrees C condenses into an insulated container holding 4.25 g of water at 4.0 degrees C. Assuming that no heat is lost to the surroundings, what will be the final temperature of the mixture?

Answer 1

heat lost by condensing steam + heat lost by water(from steam)changing to final T + heat gained by cold water moving to final T = 0

[mass steam x (-heat vap)] + [(mass steam(H2O) x specific heat H2O x (Tfinal-Tinitial)] + [mass cool H2O x specific heat H2O x (Tfinal-Tinitial)] = 0

Solve for Tfinal.