Asked by Shadow

I need to write the total ionic equation for this equation.

Copper(ii)sulfate + iron = iron(iii)+ copper.

Won't it be Cu2+ + SO4-2 + Fe = Fe3+ + Cu ?
The answer key say
3Cu2+ + 3SO4-2 + 2Fe = 2Fe3+ + 3SO4-2 + 3Cu

Where did they get the sulfate for the product from? Didn't the words equation say "iron(iii)+ copper."? Thanks
Answered by DrBob222
Your first statement(the words equation) is not correct because there is no sulfate on the product side. It should be
Copper(ii)sulfate + iron = iron(iii) sulfate + copper.
Answered by Shadow
The world equation didn't have any sulfate on the product side :(. I'm guessing such formula can't be right since how can there be sulfate on one side and there none on the other. So the words equation is wrong right? Thanks
Answered by DrBob222
Yes the word equation is wrong. Just an omission in the text.
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