Asked by p

A photon interacts with a ground state electron in a hydrogen atom and is absorbed. The electron is ejected from the atom and exhibits a de Broglie wavelength of 4.548 x 10^-10m. Determine the frequency (in hz) of the interacting photon.

i got 1.45691908531e-24 but it is wrong :(
Answered by Anonymous
9.14E18
Answered by Anonymous
9.14E18 is wrong

can you please explain how you got this number


Answered by Chemgam
E = P^2/2Me + E(first ionization)

P= h / BroglieWavelength

E(first ionization)=21.7*10^-19

Me= 9.1*10^-31

h= 6.626*10^-34

frecuency(hz)= E / h
Answered by Anonymous
Yup, it was meant to be wrong.

I don't like cheats.
Answered by Anonymous
when you gave the people wrong answer and you know that it is wrong, this is the pure cheating, stupid..!!
Answered by helper
5.043661*10^15
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