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A pressure vessel contains a large volume of CO2 gas at 10 atm pressure. A membrane composed of a poly(ether ketone) polymer wi...Asked by Ling
(a) A pressure vessel contains a large volume of CO2 gas at 10 atm pressure. A membrane composed of a poly(ether ketone) polymer with thickness 100 microns and net effective area of 100 cm2 covers a small perforated port in the container. The solubility of CO2 at 10 atm is 6.97 x 10-4 moles/cm3 at 35 C. The diffusivity of CO2 in the polymer is known to be 2.29 x 10-8 cm2/s at this temperature. How long will it take for 0.001 moles of CO2 to leak from the container at steady-state? Assume that the amount of carbon dioxide in the surroundings is insignificant. Express your answer in hours.
(b) If the diffusivity is observed to double when the temperature is increased by 10 degrees C, what is the activation energy for diffusion? Express your answer in units of eV.
(b) If the diffusivity is observed to double when the temperature is increased by 10 degrees C, what is the activation energy for diffusion? Express your answer in units of eV.
Answers
Answered by
c
conversion for seconds to hours is 60*60 or multiply 3600.
Answered by
go
could you please explain the formula
i tried everything
thanks for your time
i tried everything
thanks for your time
Answered by
po
18
Answered by
helper
18
Answered by
Anonymous
Thanx
Answered by
c
So what is a) and what is b)?
Answered by
ani
18 is not right
Answered by
martin
someone please help regarding answer of a and b. 18 is not showing green check
Answered by
Chemgam
Same here. Received a red X on the answer.
Answered by
which
formula for formula in #8
Answered by
Anonymous
4.5
Answered by
Anonymous
WONG ANSWER
Answered by
martin
what would be answer of b. would it be 45
Answered by
Ling
B) is not 45 and A) is not 18
Answered by
Anonymous
Impossible for someone to explain
Answered by
Anonymous
a) 1.74
Answered by
qwerty
thanks
Answered by
Ling
Thanks
Answered by
c
Thanks for a) any thoughts on b)?
Answered by
martin
somebody please tell the answer of b. I tried with all equation.
D=D0e^-Ea/RT
Created Eq.1 for 35+273K
and Eq.2 for 45+273k
i got Ea 1.55*10^4J/mol
even after conversion with j/mol to EV not getting green check
1KJ/mol=1.03*10^-2
if some body got green check please suggest me.
D=D0e^-Ea/RT
Created Eq.1 for 35+273K
and Eq.2 for 45+273k
i got Ea 1.55*10^4J/mol
even after conversion with j/mol to EV not getting green check
1KJ/mol=1.03*10^-2
if some body got green check please suggest me.
Answered by
Anonymous
Suggestion: do the work yourself rather than cheating. If you're desparate for a green tick, draw one in a graphics program
Answered by
Chemical Engineer
MIT the best university in the world. why are you cheating? whay are you not reading and understand the leacture?
Bad student >>>
Bad student >>>
Answered by
qpt
how to convert j/mol to EV?
Answered by
martin
1KJ/mol=1.03*10^-2EV
please somebody tell about b
please somebody tell about b
Answered by
Chemical Engineer
return to lecture and you get b
Answered by
Chemical Engineer
this is Honor. Please stop cheating
this is not useful for you
this is not useful for you
Answered by
qwerty
b=0.551
Answered by
Ling
Thank you
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