Asked by gina
The total pressure in a vessel containing hydrogen collected over water at 25degrees Celsius was 0.8atm. the vapor pressure of water at the temperature is 23.8torr. What was the pressure of the oxygen in torr?
Answers
Answered by
DrBob222
Ptotal = pO2 + pH2O
You want p in atm?
Convert 23.8 torr to atm.
0.8 atm = pO2 + (23.8/760)
Solve for pO2.
You want p in torr?
Convert 0.8 atm to torr
0.8*760 = pO2 + 23.8
Solve for pO2.
You want p in atm?
Convert 23.8 torr to atm.
0.8 atm = pO2 + (23.8/760)
Solve for pO2.
You want p in torr?
Convert 0.8 atm to torr
0.8*760 = pO2 + 23.8
Solve for pO2.
Answered by
Gina
p in atm?
0.8atm = pO2 +0.031
0.8-0.031 = pO2
0.769atm = pO2
p in torr?
608 = pO2 + 23.8
608-23.8 = pO2
584.2 torr = pO2
0.8atm = pO2 +0.031
0.8-0.031 = pO2
0.769atm = pO2
p in torr?
608 = pO2 + 23.8
608-23.8 = pO2
584.2 torr = pO2
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