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A photon interacts with a ground state electron in a hydrogen atom and is absorbed. The electron is ejected from the atom and e...Asked by Ling
A photon interacts with a ground state electron in a hydrogen atom and is absorbed. The electron is ejected from the atom and exhibits a de Broglie wavelength of 5.908 X 10^-10m . Determine the frequency (in hz) of the interacting photon.
Answers
Answered by
qpt
frequency(wavelength)=speed of light.
solve for frquency.
solve for frquency.
Answered by
c
How do you input the data into the formula?
Answered by
Anonymous
2.3E19
Answered by
qwerty
E = P^2/2Me + E(first ionization)
P= h / BroglieWavelength
E(first ionization)=21.7*10^-19
Me= 9.1*10^-31
h= 6.626*10^-34
frecuency(hz)= E / h
P= h / BroglieWavelength
E(first ionization)=21.7*10^-19
Me= 9.1*10^-31
h= 6.626*10^-34
frecuency(hz)= E / h
Answered by
Ling
Thank you
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