A photon interacts with a ground state electron in a hydrogen atom and is absorbed. The electron is ejected from the atom and exhibits a de Broglie wavelength of 5.908 X 10^-10m . Determine the frequency (in hz) of the interacting photon.

Answer 1

frequency(wavelength)=speed of light.
solve for frquency.

Answer 2

How do you input the data into the formula?

Answer 3

2.3E19

Answer 4

E = P^2/2Me + E(first ionization)

P= h / BroglieWavelength

E(first ionization)=21.7*10^-19

Me= 9.1*10^-31

h= 6.626*10^-34

frecuency(hz)= E / h

Answer 5

Thank you