Question
The reaction between hydrogen and chlorine gases gives hydrogen chloride gas in the following reaction:
H2(g) + Cl2(g) = 2HCl(g)
It is found experimentally that 1 mole of H2 gas reacts with 1 mole of Cl2 gas at constant temperature and pressure, to release 184 kJ of heat. What is the enthalpy change for this reaction?
∆h=2*(-184kJ mol^-1)
= -368kJ mol^-1
is this the right answer
H2(g) + Cl2(g) = 2HCl(g)
It is found experimentally that 1 mole of H2 gas reacts with 1 mole of Cl2 gas at constant temperature and pressure, to release 184 kJ of heat. What is the enthalpy change for this reaction?
∆h=2*(-184kJ mol^-1)
= -368kJ mol^-1
is this the right answer
Answers
I don't think so. dH rxn is -184 kJ.
thanks
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