Asked by Anne
solve (Z^2)+5=-4/Z^2
how do i solve it??
the answer is +2or-2, or, +or -i. but i really don't know how to get this answer.i tried to multiply both side by Z^2, but i think it just made it more comlicated and i didn't get the right answer at the end...can someone please explain?? thanks!!
how do i solve it??
the answer is +2or-2, or, +or -i. but i really don't know how to get this answer.i tried to multiply both side by Z^2, but i think it just made it more comlicated and i didn't get the right answer at the end...can someone please explain?? thanks!!
Answers
Answered by
Reiny
Yes, you are on the right track
After multiplying by z^2 and rearranging you would have
z^4 + 5z^2 +4 = 0
this factors to
(z^2+1)(z^2+4) = 0
then z^ = -1 or z^2 = -4
there is not real number solution but if you use complex numbers where √-1 = i
z = ±i or z = ±2i
After multiplying by z^2 and rearranging you would have
z^4 + 5z^2 +4 = 0
this factors to
(z^2+1)(z^2+4) = 0
then z^ = -1 or z^2 = -4
there is not real number solution but if you use complex numbers where √-1 = i
z = ±i or z = ±2i
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