Asked by Kate
Steve McSpoke left home on his bicycle at 8am, traveling at 18km/h. At 10am, Steve's brother set out after him on a motorcycle, following the same route. The motorcycle traveled at 54km/h. How long had steve traveled when his brother overtook him?
Answers
Answered by
Reiny
Steve's brother time to catch-up --- t hrs
Steve's time to catch-up by brother -- t+2
54t = 18(t+2)
54t = 18t + 36
36t = 36
t = 1
Steve had biked for 3 hours, when his brother overtook him.
Steve's time to catch-up by brother -- t+2
54t = 18(t+2)
54t = 18t + 36
36t = 36
t = 1
Steve had biked for 3 hours, when his brother overtook him.
Answered by
Kate
thanks
Answered by
Kate
Also, how far had steve traveled when his brother overtook him?
Answered by
Reiny
simply sub in the value of t = 1 into both distances., you will obviously get the same answer since they both went the same distance.
Answered by
Kate
Reiny, how can you show me how to do the last part wirten out?
Thank you so much!
Thank you so much!
Answered by
Kate
neverminds. I got it.
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