Asked by Krysta Q
Jamila left home on her bike at 11:00 AM traveling at 12 km/h. At noon, her sister Tamantha set out after her following the same route. If Tamantha's motorcycle traveled 28km/h, what time did Tamantha overtake Jamila?
Answers
Answered by
Reiny
Jamila went 12t km, (remember D=R*T)
Tamantha went 28(t-1) , she went 1 hour less than Jamila
But when she overtakes her sister, they went the same distance, so
28(t-1_ = 12t
28t - 12t = 28
16t=28
t = 1.75 which is 1 hour and 45 minutes
so Tamantha caught up with her sister 12:45 pm
Tamantha went 28(t-1) , she went 1 hour less than Jamila
But when she overtakes her sister, they went the same distance, so
28(t-1_ = 12t
28t - 12t = 28
16t=28
t = 1.75 which is 1 hour and 45 minutes
so Tamantha caught up with her sister 12:45 pm
Answered by
Krysta Q
Thank you!
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.