Asked by Rebecca
Find the speed and period of a satellite that orbits Mars 175 km above it's surface. (The average radius of Mars is 3.40 x 10^6; and it's mass is 6.42 x 10^23. Use all necessary formulas and show all clear-working, to enable me understand how you arrived at your answer.
Answers
Answered by
Elena
mv²/R=GmM/R²
v=sqrt(GM/R )=sqrt{6.67•10⁻¹¹•6.42•10²³ /(3.40 •10⁶+175 000)}=3.46•10³ m/s.
T=2πR/v=2•3.14•(3.40 •10⁶+175 000)/ 3.46•10³ =6.5•10³ s=1.8 h
v=sqrt(GM/R )=sqrt{6.67•10⁻¹¹•6.42•10²³ /(3.40 •10⁶+175 000)}=3.46•10³ m/s.
T=2πR/v=2•3.14•(3.40 •10⁶+175 000)/ 3.46•10³ =6.5•10³ s=1.8 h
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