form a polynomial with real coefficients have given degree and zeros.
degree 5, zeros 9, -i; 8+i

please show work

Answers

Answered by Steve
complex roots are in pairs, so we have
(x-9)(x+i)(x-i)(x-(8+i))(x-(8-i))
(x-9)(x^2+1)((x-8)^2 + 1)

. . .
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions