Asked by Breanna
Form a polynomial f(x) with real coeffiecients having the given degree and zeros.
degree 4, zeros 3, multiplicity 2; 6i
f(x)=a()
Can someone show how to do this. I have tried and do not have a clue. I am lost!!! So, please show work.
degree 4, zeros 3, multiplicity 2; 6i
f(x)=a()
Can someone show how to do this. I have tried and do not have a clue. I am lost!!! So, please show work.
Answers
Answered by
Steve
by the time you get to calculus, you should know how to use the roots to form a polynomial. If you tried, you should show what you have tried, and where you got stuck.
If a is a root of f(x)=0, (x-a) is a factor of f(x).
Since complex roots come in pairs, -6i is also a root, so
f(x) = (x-3)(x-3)(x-6i)(x+6i)
= (x-3)^2 (x^2+36)
saying you do not have a clue indicates either
a) you have woefully neglected your studies, or
b) you are just lazy and want someone else to do your work, or
(c) both of the above.
If a is a root of f(x)=0, (x-a) is a factor of f(x).
Since complex roots come in pairs, -6i is also a root, so
f(x) = (x-3)(x-3)(x-6i)(x+6i)
= (x-3)^2 (x^2+36)
saying you do not have a clue indicates either
a) you have woefully neglected your studies, or
b) you are just lazy and want someone else to do your work, or
(c) both of the above.