Asked by Zack
evaluate each limit, if it exists
[(2+x)^2 - 16]/ (x-2)
what do I do?
[(2+x)^2 - 16]/ (x-2)
what do I do?
Answers
Answered by
drwls
At what value of x do you want the limit? Is it at x = 2, where the denominator vanishes?
The numerator is the difference of two squares, andcan be written
(2 + x -4)(2 + x +4)= (x-2)(x+6)
Cancel out the x-2 therms in numerator and denominator anbd you are left with
x + 6. You can easily evaluate that at any value of x, including x=2
The numerator is the difference of two squares, andcan be written
(2 + x -4)(2 + x +4)= (x-2)(x+6)
Cancel out the x-2 therms in numerator and denominator anbd you are left with
x + 6. You can easily evaluate that at any value of x, including x=2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.