Asked by fathima
8.58g of coastic soada was dissolved to produce a solution of 500cm3 .to neutralize 50cm3 of this solution 15cm3 of 0.4M HCl was consumed .(coastic soada = Na2CO3.XH2O ) find the value of X?
Answers
Answered by
DrBob222
Note the correct spelling of caustic soda. Also, correct sentence structure helps us read these problems better.
How many mols HCl did you use? That's M x L = 0.4M x 0.015L = 0.006.
How many grams were in the solution you titrated. That's 8.58 x 50/500 = 0.858 g.
Then mols = grams/molar mass and rearrange to molar mass = grams/mols.
0.858/0.006 = about 143.
Subtract Na2CO3 = -106
Remainder is 37 and 37/18 = 2.05 mols and I would round that to 2.0 for X.
How many mols HCl did you use? That's M x L = 0.4M x 0.015L = 0.006.
How many grams were in the solution you titrated. That's 8.58 x 50/500 = 0.858 g.
Then mols = grams/molar mass and rearrange to molar mass = grams/mols.
0.858/0.006 = about 143.
Subtract Na2CO3 = -106
Remainder is 37 and 37/18 = 2.05 mols and I would round that to 2.0 for X.
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