Asked by Anonymous
How many grams of NaNO2 should be dissolved in 500cm3 solution of nitrous acid (HNO2) with concentration of 0.03mol/dm3 if we wish the solution to show a pH of 3.2
Ka = 4.5 * 10^-4
M(NaNO2) = 69 g/mol
Ka = 4.5 * 10^-4
M(NaNO2) = 69 g/mol
Answers
Answered by
DrBob222
Use the Henderson-Hasselbalch equation.
pH = pKa + log (base)/(acid)
You have pH, pKa, and (acid); solve for (base) and convert to grams in 500 cc.
pH = pKa + log (base)/(acid)
You have pH, pKa, and (acid); solve for (base) and convert to grams in 500 cc.
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