Asked by Shadow
Thank you for the informative answer yesterday. I hope you can help me with this one too. Thanks
S(subscript 8) + O( subscript 2) -> SO3
Could you explain why it O3 when S valence is -2? Thanks
S(subscript 8) + O( subscript 2) -> SO3
Could you explain why it O3 when S valence is -2? Thanks
Answers
Answered by
DrBob222
Yes. S is +6 in SO3. Each O is -2; 3*-2 = -6 so for SO3 to be neutral (as all compounds are) S must be +6. That's part of the problem, I suppose, and S DOES have -2 in H2S and the sulfides (such as Na2S, K2S, BaS, etc) but S may have valences of -2, 0, +4 and +6 and those are quite common. SO2 is an example of +4. Hope this helps.
Answered by
Shadow
So since it S3O6, it was reduce to SO3?
Answered by
DrBob222
Yes, SO3 is the empirical formula.
Answered by
DrBob222
Yes, SO3 is the empirical formula. It may be the molecular formula, also.
Answered by
Shadow
When you write the formula in word equation would it be : Octasilicon and oxygen reacted to produce sulfur trioxide?
Would this be the balance equation?
S8 + 12O2 -> 8SO3
Would this be the balance equation?
S8 + 12O2 -> 8SO3
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