Question
A 2.6kggold bar at 90C is dropped into a 0.21kg of water at 23C. What is the finl temperature? Assume the specific heat of gold is 129 J/kg C. Answer in units of C
Answers
Elena
c₁=129 J/kg•℃, m₁ =2.6 kg,t₁ =90℃
c₂=4180 J/kg•℃,m₂=0.21 kg, t₂=23℃
t=?
Q₁=c₁m₁(t₁-t)
Q₂=c₂m₂(t-t₂)
Q₁=Q₂ =>
c₁m₁(t₁-t) = c₂m₂(t-t₂)
Solve for t
c₂=4180 J/kg•℃,m₂=0.21 kg, t₂=23℃
t=?
Q₁=c₁m₁(t₁-t)
Q₂=c₂m₂(t-t₂)
Q₁=Q₂ =>
c₁m₁(t₁-t) = c₂m₂(t-t₂)
Solve for t