Question

Suppose that an object is dropped from a height of h meters and hits the ground with a velocity of v meters per second. Then v= sqrt19.6h. If an object hits the ground with a velocity of 24.2 meters per second, from what height was it dropped?


Carry your intermediate computations to at least four decimal places, and round your answer to the nearest tenth.

Answer 1

just plug in your value:
24.2 = √(19.6 h)
√h = 24.2/√19.6
h = (24.2/√19.6)^2 = 29.88 m

or

I know from physics that
h = 4.905 t^2 gives you the height from which an object was dropped after t seconds ,
and v = 9.81 t gives you the velocity after t seconds

so 24.2 = 9.81 t
t = 2.46687..
h = 4.905(2.46687..)^2= appr 29.85 m

Answer 2

If your rounding to the nearent tenth though that can't plug in. I'm so confused.

Answer 3

The answer is 32.1 meters

Answer 4

Suppose a pendulum is L meters long. The time, t, in seconds that it takes to swing back and forth once is given by t=2.01\sqrt()L. If a pendulum is 20.25 meters long, how long does it take to swing back and forth once?
Round your answer to the nearest tenth.