Asked by Bryan
Suppose that an object is dropped from a height of h meters and hits the ground with a velocity of v meters per second. Then v= sqrt19.6h. If an object hits the ground with a velocity of 24.2 meters per second, from what height was it dropped?
Carry your intermediate computations to at least four decimal places, and round your answer to the nearest tenth.
Carry your intermediate computations to at least four decimal places, and round your answer to the nearest tenth.
Answers
Answered by
Reiny
just plug in your value:
24.2 = √(19.6 h)
√h = 24.2/√19.6
h = (24.2/√19.6)^2 = 29.88 m
or
I know from physics that
h = 4.905 t^2 gives you the height from which an object was dropped after t seconds ,
and v = 9.81 t gives you the velocity after t seconds
so 24.2 = 9.81 t
t = 2.46687..
h = 4.905(2.46687..)^2= appr 29.85 m
24.2 = √(19.6 h)
√h = 24.2/√19.6
h = (24.2/√19.6)^2 = 29.88 m
or
I know from physics that
h = 4.905 t^2 gives you the height from which an object was dropped after t seconds ,
and v = 9.81 t gives you the velocity after t seconds
so 24.2 = 9.81 t
t = 2.46687..
h = 4.905(2.46687..)^2= appr 29.85 m
Answered by
Bad at math
If your rounding to the nearent tenth though that can't plug in. I'm so confused.
Answered by
Arianna
The answer is 32.1 meters
Answer
Suppose a pendulum is L meters long. The time, t, in seconds that it takes to swing back and forth once is given by t=2.01\sqrt()L. If a pendulum is 20.25 meters long, how long does it take to swing back and forth once?
Round your answer to the nearest tenth.
Round your answer to the nearest tenth.
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