Question



Calculate the molarity of the K+ ion in a solution prepared by adding of 5.55 g of K2SO4 to enough water to form 0.500 L of solution.
mols K2SO4 = grams/molar mass
M K2SO4 = mols/L
M K^+ = twice that because there are 2 K ions in 1 molecule of K2SO4.
25 grams of K2SO4 is added to 2500 mL of water, what will be the molarity of this solution?

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