Asked by yaya
Given a function
f(x)2/3x^3+5/2x^2-3x.
a) Find
i. The inflection point.
ii. The y-intercept and x-intercept.
b) Sketch the graph of f(x).
i have already try it..but i don't understand.. which graph that is true.. the first or second ? and how to calculate the x,y intercept,and inflection point? i hope you can help me to solve this ..
f(x)2/3x^3+5/2x^2-3x.
a) Find
i. The inflection point.
ii. The y-intercept and x-intercept.
b) Sketch the graph of f(x).
i have already try it..but i don't understand.. which graph that is true.. the first or second ? and how to calculate the x,y intercept,and inflection point? i hope you can help me to solve this ..
Answers
Answered by
Steve
y = 2/3 x^3 + 5/2 x^2 - 3x
y' = 2x^2 + 5x - 3
y'' = 4x + 5
inflection where y''=0 -- at x=-5/4
intercepts at (0,0)
and at x = 3/8 (-5±√57)
Looks like you need to review the meanings of 1st and second derivatives.
y' = 2x^2 + 5x - 3
y'' = 4x + 5
inflection where y''=0 -- at x=-5/4
intercepts at (0,0)
and at x = 3/8 (-5±√57)
Looks like you need to review the meanings of 1st and second derivatives.
Answered by
Elsi
remember that the first derivative gives you the max's and min's and the second derivative tells you concavity and inflection points
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