Question
HOW DO YOU FIND THE VELOCITY OF A 20 kg SOLID CYLINDER WITH A .25 m RADIUS WHEN IT IS RELEASED FROM THE TOP OF A 10 m LONG RAMP INCLINED AT 30 DEGREES?
The potential energy at the top is mg10/sin30
The Ke at the bottom is 1/2 mv^2, plus 1/2 Iw^2
but w= v/r
so KE = 1/2 mv^2 + 1/2 I v^2/r^2
set that equal to PE, and solve for V.
YOu have to lookup or determine the moment of inertia for a solid cylinder.
The potential energy at the top is mg10/sin30
The Ke at the bottom is 1/2 mv^2, plus 1/2 Iw^2
but w= v/r
so KE = 1/2 mv^2 + 1/2 I v^2/r^2
set that equal to PE, and solve for V.
YOu have to lookup or determine the moment of inertia for a solid cylinder.