Question
find the velocity with which it hits the ground when a body is projected horizontally from top of a tower 100 meter high with a velocity of 9.8 meter per second.
Answers
Steve
Vx = 9.8
Vy = √(2as) = √(2*9.8*100) = 44.27
final v = √(Vx^2 + Vy^2)
Vy = √(2as) = √(2*9.8*100) = 44.27
final v = √(Vx^2 + Vy^2)