Find the velocity, v(t), for an object moving along the x-axis if the acceleration, a(t), is a(t) = 2t + sin(t) and v(0) = 4.

Question

v(t) = t2 + cos(t) + 3
v(t) = 2 + cos(t) + 1<- my answer
v(t) = t2 − cos(t) + 5
v(t) = t2 + sin(t) + 4

Answer 1

You have found da/dt. Instead, you are given a, so

v(t) = ∫v dt = t^2 - cos(t) + C
since v(0) = 4, C=5

v(t) = t^2 - cos(t) + 5