wf^2 = wi^2 + 2 (alpha) * (angle of rotation (delta theta))
delta theta = (1.76^2 - 0.77^2) / 2*0.29
delta theta = 2.36
(check me on my math))
A machine part rotates at an angular speed
of 0.77 rad/s; its speed is then increased to
1.76 rad/s using an angular acceleration of
0.29 rad/s
2
.
Find the angle through which the part rotates before reaching this final speed.
Answer in units of rad
1 answer