Asked by Morgan

What are the steps in finding the balanced equation for the complete combustion of benzene?

Answers

Answered by kazz
Well, you need for Balanced Writing about Combustion of Benzene.
Since Benzene is an Aromatic Hydrocarbon, YOU ARE ATTENDING ITS MOLECULES CONTAIN CARBON- AND HYDROGEN-ATOMs, no more species.
Now, YOU MAY STATE ITS CHEMICAL PRODUCTs HAVE TO RESULT CARBON DIOXIDE (e.g. CO2) AND WATER (e.g. H2O) LIKE VAPOURs.
So, you begin writing

C6H6(l) + O2(g) ---> CO2(g) + H2O(g)

WHICH CARRY OUT ALL CITED SPECIES.
THERE IS A TROUBLE : Chemical Writing isn't balanced one.

Step 1) YOU MULTIPLY BY 6 CO2 AT RIGHT TERM TO BALANCE Carbon Atoms

C6H6(l) + O2(g) ---> 6 CO2(g) + H2O(g)

Step 2) YOU MULTIPLY BY 3 H2O AT RIGHT TERM TO BALANCE Hydrogen Atoms

C6H6(l) + O2(g) ---> 6 CO2(g) + 3 H2O(g)

Step 3) YOU MULTIPLY BY "15/2" O2 AT LEFT TERM TO BALANCE Oxygen Atoms

C6H6(l) + (15/2) O2(g) ---> 6 CO2(g) + 3 H2O(g)

Step 4) YOU MULTIPLY BY 4 ALL THE SPECIES AT TWO TERMs TO GIVE Whole Coefficients

2 C6H6(l) + 15 O2(g) ---> 12 CO2(g) + 6 H2O(g)


WARNING!!
I DISCUSSED COMPLETE COMBUSTION PROCESS DESPITE THIS PHENOMENON RESULTS A DIFFICULT ONE.
BENZENE IS AN "AROMATIC HYDROCARBON" SO IT BURNS DIFFICULTLY.
Usually, Benzene leaves up forming stinking fumes rich by itself since it keep unchanged among Burning Flames.

I hope this helps you.
Answered by DrBob222
Benzene is a hydrocarbon, C6H6
Hydrocarbons combust with oxygen to produce CO2 and H2O
C6H6 + O2 ==> CO2 + H2O
Balance by trial and error. But you can help the "trial" part by some snooping around. For example, I look at C6H6 so I know that must produce 6CO2 so I place a 6 coefficient for CO2.
C6H6 + O2 ==> 6CO2 + H2O
Then I see 6H on the left and I know immediately to place a 3 for H2O on the right.
C6H6 + O2 ==> 6CO2 + 3H2O
Now I count O on the right and I see 15. On the left I can get that number ONLY with a fraction for O2. That fraction is 15/2 BUT we usually don't write these equations with fractions so I multiply everything by 2 in order to clear the fraction.. That gives 2C6H6 + 15O2 ==> 12CO2 + 6H2O
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