a bike passes a lamp post at the crest of hill at 4.5 m/s. she accelerates down the hill at the rate of 0.04 m/s squared for 12 seconds. how far does she move down the hill during this time ?

Answer 1

s=v₀t+at²/2,
v₀= 4.5 m/s,
a= 0.04 m/s²,
t= 12s

Answer 2

d=V(initial)*time+1/2at^2
d=(4.5)(12)=1/2(0.40)(12)
d=54+1/2(4.8)
d=54+2.4
d=56.4m