Doesn't Kepler's law apply?
T^2/r^3=constant=for Earth T^2/R^3
r^3=7^2*(92millionmiles)^3/1year^2
r= 92million miles * cuberoot(49)
Imagine that a new asteroid is discovered in
the solar system with a circular orbit and an
orbital period of 7 years.
What is the average distance of this object
from the Sun in Earth units?
1 answer