Asked by Hamp
Consider an asteroid with a radius of 15.5 km and a mass of 3.46E+15 kg. Assume the asteroid is roughly spherical. What is the acceleration due to gravity on the surface of the asteroid?
Suppose the asteroid spins about an axis through its center, like the Earth, with a rotational period T. What is the smallest value $T$ can have before loose rocks on the asteroid's equator begin to fly off the surface?
Suppose the asteroid spins about an axis through its center, like the Earth, with a rotational period T. What is the smallest value $T$ can have before loose rocks on the asteroid's equator begin to fly off the surface?
Answers
Answered by
bobpursley
Fg=GM/radius^2
centripetal acceleration=w^r r
where w=2PI/PeriodT
centripetal acceleration=w^r r
where w=2PI/PeriodT
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