A 6.1 kg bowling ball is lifted 2.4 m into a

storage rack.
The acceleration of gravity is 9.8 m/s
2
.
Calculate the increase in the ball’s potential
energy.
Answer in units of J

2 answers

cvdf
PE= (M)(G)(H)
PE= (6.1)(9.8)(2.4)
PE= 155.232 J