Question

Use the partial ractions to find
The integral (3x^2-x+2)/(x-1)(x^2+1) dx

Answer 1

the integrand is x/(x^2+1)+2/(x-1)
so integral is

1/2 log (x^2+1) + 2 log(x-1)
= log [√(x^2+1)/(x-1)^2]

Answer 2

oops
log [√(x^2+1)*(x-1)^2]