Question

How do you take the partial derivative of y = (1200z1z2)^1/2 in respect to z1. Please note z1 and z2 are variables.

f'z1 = (1200^1/2)(z1^1/2)(z2^1/2)
f'z1 = ??


the answer is...

f'z1 = ((1200^1/2)(z2^1/2))/((2(z1^1/2))

but I do not know how to get this answer. Please help me by providing full steps and explanations.

Answer 1

nvrm I figured it out myself