Asked by Anonymous
How do you take the partial derivative of y = (1200z1z2)^1/2 in respect to z1. Please note z1 and z2 are variables.
f'z1 = (1200^1/2)(z1^1/2)(z2^1/2)
f'z1 = ??
the answer is...
f'z1 = ((1200^1/2)(z2^1/2))/((2(z1^1/2))
but I do not know how to get this answer. Please help me by providing full steps and explanations.
f'z1 = (1200^1/2)(z1^1/2)(z2^1/2)
f'z1 = ??
the answer is...
f'z1 = ((1200^1/2)(z2^1/2))/((2(z1^1/2))
but I do not know how to get this answer. Please help me by providing full steps and explanations.
Answers
Answered by
Anonymous
nvrm I figured it out myself
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.