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Asked by Anonymous

It takes 2.5 J of energy to stretch a helical spring by 15 cm. Determine the spring
constant.
12 years ago

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Answered by Elena
PE=kx²/2
k=2•PE/ x²=
=2•2.5/0.15²=222 N/m
12 years ago
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It takes 2.5 J of energy to stretch a helical spring by 15 cm. Determine the spring
constant.

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