Question
It takes 208.4 kJ of energy to remove one mol of electrons from the atoms on the surface of rubidium metal. If rubidium metal metal is irradiated with 254-nm light, what is the maximum kinetic energy the released electrons can have?
Answers
208,400 J/mol x (1/6.02E23) = ? work function.
E of photon = hc/wavlength = 6.626E-34*3E8/254E-9 = x
Take the difference between x and ? above and that is the maximum energy of an ejected electron which is KE = 1/2 mv<sup>2</sup>. Then solve for v in m/s.
E of photon = hc/wavlength = 6.626E-34*3E8/254E-9 = x
Take the difference between x and ? above and that is the maximum energy of an ejected electron which is KE = 1/2 mv<sup>2</sup>. Then solve for v in m/s.