Question
A plank with m=0.12 kg and 50cm long has one mass of m1=0.11kg sitting on one end and a m2=0.055kg at the other end. Where should the pivot point be to balance the plank?
Answers
Betsalel
I figured the equation out
Xcg=(m1x1+m2x2+m3(L/2))/(m1+m2+m3)
m1 = 0.055kg
x1 = 0cm
m2 = 0.11kg
x2 = 50cm
for the plank you need to add
m3 = 0.12kg
and distance is L=50cm
it calculates to Xcg=29.825cm
Xcg=(m1x1+m2x2+m3(L/2))/(m1+m2+m3)
m1 = 0.055kg
x1 = 0cm
m2 = 0.11kg
x2 = 50cm
for the plank you need to add
m3 = 0.12kg
and distance is L=50cm
it calculates to Xcg=29.825cm