Asked by Sarah
More log/exponential equations
log2 x + log2(x+2) =3
log2 x + log2(x+2) =3
Answers
Answered by
Steve
log2 (x(x+2)) = 3
x(x+2) = 2^3 = 8
x^2 + 2x - 8 = 0
(x+4)(x-2) = 0
x=2
throw out x=-4, since logx is not defined for x<0
x(x+2) = 2^3 = 8
x^2 + 2x - 8 = 0
(x+4)(x-2) = 0
x=2
throw out x=-4, since logx is not defined for x<0
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