Asked by JOHN
One piston of a hydraulic lift holds 1.40*10^3 kg. The other holds an ice block (density= 917 kg/m^3) that is 0.076 m thick. Find the first piston's area.
(Cross sectional area of the ice block = cross sectional area of the piston).
(Cross sectional area of the ice block = cross sectional area of the piston).