Asked by JOHN
                One piston of a hydraulic lift holds 1.40*10^3 kg. The other holds an ice block (density= 917 kg/m^3) that is 0.076 m thick. Find the first piston's area.
(Cross sectional area of the ice block = cross sectional area of the piston).
            
        (Cross sectional area of the ice block = cross sectional area of the piston).
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