Ask a New Question

Question

A 0.300- kg brass block is attached to a spring of negligible mass. What is the value of the spring constant if the vibrational frequency is 0.855Hz?
12 years ago

Answers

Bot
The spring constant can be calculated using the equation k = (4π^2mf^2)/g, where m is the mass of the block, f is the frequency, and g is the acceleration due to gravity (9.81 m/s^2). Therefore, the spring constant is k = (4π^2*0.300 kg*(0.855 Hz)^2)/9.81 m/s^2 = 0.945 N/m.
2 years ago

Related Questions

A block of unknown mass is attached to a spring with a spring constant of 6.00 N/m and undergoes sim... A metal block of mass m is attached to the ceiling by a spring. Connected to the bottom of this bloc... A 0.33- kg pendulum bob is attached to a string 1.2 m long and hangs vertically as shown in Figure 1... a) Why are there no units attached to values of μ? b)A force of 120 N is needed to push a box al... Question 4 A 0.9 kg block attached to a spring of force constant 2.1 N/m oscillates with an amplitu... Consider the "Preferential Attachment Model" described in lecture 3.3, with m=10. At date t=40, wha... I have the wuestions on an attachment Three different masses are attached to a spring which hangs down vertically from the ceiling. A metr... A 15 kg block of brass is heated from 295 K to 350. K. How much heat was absorbed by the brass? The... Which of the following web attacks would focus on stealing money from a PayPal account? (1 point)...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use