Question
An airplane flies with a speed of 425 mph and a heading of 63°. If the heading of the wind is 24°and the speed of the wind is 31 mph, what is the heading of the plane and the ground speed?
I've done a couple questions like this but still a little fuzzy on setting it up, any help would be greatly appreciated.
I've done a couple questions like this but still a little fuzzy on setting it up, any help would be greatly appreciated.
Answers
V = 425mi/h @ 63o + 31mi/h @ 24o
X = 425*cos63 + 31*cos24 = 221.3 mi/h.
Y = 425*sin63 + 31*sin24 = 391.3 mi/hr.
tanA = Y/X = 391.3/221.3 = 1.7681
A = 60.5o. = Direction of plane.
V = X/cosA = 221.3/cos60.5 = 431 mi/h =
Velocity of plane.
X = 425*cos63 + 31*cos24 = 221.3 mi/h.
Y = 425*sin63 + 31*sin24 = 391.3 mi/hr.
tanA = Y/X = 391.3/221.3 = 1.7681
A = 60.5o. = Direction of plane.
V = X/cosA = 221.3/cos60.5 = 431 mi/h =
Velocity of plane.
Related Questions
An airplane flies on a compass heading of 90° at 310 mph. The wind affecting the plane is blowing fr...
An airplane is flying from Montreal to Vancouver. The wind is blowing from the west at 60km/hour. Th...
An airplane is travelling at a speed of 600 mph on a heading of 345 degrees. There is a wind moving...
A new passenger airplane is flying from Vancouver heading overseas to Asia. The wind is blowing from...