Asked by DEEPAK
AT WHAT HEIGHT ABOVE THE EARTH'S SURFACE DOES THE ACCELERATION DUE TO GRAVITY FALL TO 1% OF ITS VALUE AT THE EARTH SURFACE
Answers
Answered by
drwls
Solve this equation for height h, in kilometers:
[6378/(6378+h)]^2 = 0.01
Note that an inverse square law is being used.
6378 is the Earth's radius in km.
[6378/(6378+h)]^2 = 0.01
Note that an inverse square law is being used.
6378 is the Earth's radius in km.
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